Question

please solve this it is urgent ​

Answer 1

Answer:

192

Step-by-step explanation:

$x + y + z = 8 \\ \\ xy + yz + zx = 20 \\ \\ ( x + y + z) = 8 \\ \\ {(x + y + z)}^{2} = {8}^{2} \\ \\ \\ {x}^{2} + {y}^{2} + {z}^{2} + xy + yz + zx = 64 \\ \\ \\ \\ \\ {x}^{2} + {y}^{2} + {z}^{2} + 20 = 64 \\ \\ {x }^{2} + {y}^{2} + {z}^{2} = 44 \\ \\ therefore \: \: \: \: \: {x}^{3} + {y}^{3} + {z}^{3} - 3xyz = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx) \\ \\ = (8)(44 - 20) \\ \\ = 8 \times 24 \\ \\ = 192.$