Question

please solve this it's important​

Answer 1

Step-by-step explanation:

=> [ (3²)^n * 3²*(3^-n/2)^2 - (3³)^n ]/(3^3m * 2³) = 1/27

=> [ 3^2n *3²*3^n - 3^3n ]/(3^3m * 2³) = 1/27

=> [3^(2n+2+n) - 3^3n ]/(3^3m*2³) = 1/27

=> 3^3n(3²-1)/(3^3m*2³) = 1/27

=> 3^3n*8/(3^3m*8) = 1/27

=> 3^3n / 3^3m = 1/3³

=> 3^(3n-3m) = 3^-3

=> 3n-3m = -3

=> 3(n-m) = -3

=> n-m = -1

=> m-n = 1