Question

Please solve this.
It's urgent............!!!!!!​

Answer 1

Answer:

area of garden is 129.5 msq. and perimeter of garden is 48 m .

Step-by-step explanation:

breadth of rectangle = diameter of semi circle

= 7 cm

therefore, radius of semi circle = diameter/2

= 7/2

= 3.5 m

total length of plot = 20 m

length of rectangle = 20 - (3.5 + 3.5)

= 13 m

area of plot = area of rectangle + area of 2 semi

circle

= 13 × 7 + 2 × 1/2 π rsq.

= 91 + 22 × 0.5 × 0.5

= 91 + 38.5

= 129.5 msq.

perimeter of plot = 2 × l + 2 × 1/2 × circumference

= 2 × 13 + 22/7 × 7

= 26 + 22

= 48 m

Answer 2

$\huge \underline \mathfrak{Solution:}$

Given,

Length of the rectangle= 20-[3.5+3.5]

= 13 m

Area of the given figure = Area of the rectangle+ Area of two semi circle

$\sf = l + b + \frac{ {\pi r}^{2} }{2} + \frac{ {\pi r}^{2} }{2} \\ \sf = l \times b + {\pi r}^{2} \\ \sf \small = (13 \times 7) + ( \frac{22}{7} \times 3.5 \times 3.5) \\ \sf = 91 + 38.5 \\ \sf = 129.5 {m}^{2}$

Perimeter of the figure

$\sf \small = 13 + 13 + (2 \times \frac{22}{7 \times 3.5} ) \\ \sf = 26 + 22 \\ \sf = 48m$