Question

please solve this it's urgent

Answer 1

This is the answer........

Answer 2

hiii!!!

here's ur answer...

31. given the side of the cubical tank = 1.2m

therefore it's volume = side³

= 1.2 × 1.2 × 1.2

= 1.728m³

32. dimensions of the cuboidal can are 15cm, 10cm and 25cm.

volume of cuboidal can = 15 × 10 × 25

= 3750cm³

hence, 3750cm³ juice can be poured in the can.

33. given the height of the circular cylinder is 14cm and radius it's base is 5cm.

CSA of the cylinder = 2πrh

= 2 × 22/7 × 5 × 14

= 44 × 5 × 2

= 440cm²

34. volume of the cube = 1331cm³

therefore side³ = 1331cm³

==> side = ³√1331

==> side = ³√11×11×11

==> side = 11cm

hence, the side of the cube is 11cm.

35. let the edge of the cube be "a"

lateral surface area of the cube = 100cm²

therefore 4a² = 100cm²

==> a² = 100/4

==> a² = 25

==> a = √25

==> a = 5

hence, the edge of the cube just 5cm.

36. total surface area of the cubical box = 294cm²

therefore 6side² = 294cm²

==> side² = 294/6

==> side² = 49

==> side = √49

==> side = 7cm

37. let side of the cube be "a"

volume of the cube = a³

volume of the new cube formed = 216 × a³

= 216a³

therefore side = ³√216a³

= 6a³

ratio between there side = 6a³ : a³

= 6 : 1

38. given the side of the cube = 2cm

volume = 2 × 2 × 2

= 8cm³

therefore volume of the new cube = 125 × 8

= 1000cm³

hence, side of the new cube = ³√1000

= 10cm

39. volume of the three cubes of side 3cm, 4cm and 5cm = (3)³ + (4)³ + (5)³

= 27 + 64 + 125

= 216cm³

therefore sides of the new cube formed after melting these 3 cubes = ³√216

= 6cm

40. the rectangular sheet if length 44cm and breadth 10cm is rolled along it's length.

therefore the height of the cylinder formed is 10cm and circumference = 44cm

circumference of the cylinder = 44cm

therefore 2πr = 44cm

==> 2 × 22/7 × r = 44cm

==> 44/7 × r = 44cm

==> r = 44/1 × 7/44

==> r = 7

radius of the base of cylinder is 7cm.

hope this helps..!!