please solve this it's urgent for me
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after simple rationalization of x we get,
x=√3-√2/√3-√2= (√3-√2)/(√3-√2)*(√3+√2)/(√3+√2) = 3-2/3-2= 1/1=1
similarly for y with (√3-√2)/(√3-√2) we get,
y=1
therefore, x²+y²+xy= (1)²+(1)²+1*1= 1+1+1=3
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