Please solve this it's urgent
I will make the answer brain list
Attachments:
Answers
Answered by
1
Answer:
The position of person from origin is 10 m West.
Explanation:
Given that,
A person moves 30 m North then 20 m east than 30 root 2 meter southwest.
The movement along north direction, Vector OY =
The movement along east direction, Vector YX=
Movement along south west direction, XZ
Vector XZ==30i + 30j
Using triangle vector law,
OX = 20i + 30j
XZ = 30i + 30j
In triangle XZO, OZ is resultant from origin.
OZ = OX-XZ
OZ = 20i + 30j - 30i - 30j
OZ = -10i
Hence, The position of person from origin is 10 m West.
The position of person from origin is 10 m West.
Explanation:
Given that,
A person moves 30 m North then 20 m east than 30 root 2 meter southwest.
The movement along north direction, Vector OY =
The movement along east direction, Vector YX=
Movement along south west direction, XZ
Vector XZ==30i + 30j
Using triangle vector law,
OX = 20i + 30j
XZ = 30i + 30j
In triangle XZO, OZ is resultant from origin.
OZ = OX-XZ
OZ = 20i + 30j - 30i - 30j
OZ = -10i
Hence, The position of person from origin is 10 m West.
Answered by
1
Answer:
10m along west
Explanation:
30 m North = 30 j^
20 m east = 20 Î
30√2 south west.
Now,
Its components :
Along x - axis = 30√2 cos 45°
= 30√2 * 1/√2
= 30 Î
Along y - axis = 30√2 sin 45°
= 30√2 * 1/√2
= 30 j^
Then,
Net movement = 30 j^ + 20 Î - 30 j^ - 30 Î
= -10 Î
This shows the displacement of 10 m towards west from origin
Hope it helps!
Similar questions