Question

please solve this it's very urgent​

Answer 1

Answer:

x = 80°

y = 60°

z  = 140°

Step-by-step explanation:

In ΔBDE, ∠BDE + ∠BED + ∠DBE = 180°(Angle Sum Property)

⇒ 30° + 90° + y = 180°

⇒y = 180°- 120°

⇒y = 60°

In ΔACD, ∠ACD + ∠ADC + ∠CAD= 180°(Angle Sum Property)

⇒ ∠ACD + 30° + 50° = 180°

⇒ ∠ACD = 180° - 80°

⇒ ∠ACD = 100°

Now,  ∠ACD + ∠ACB = 180°( Linear pair)

⇒100° + x = 180°

⇒x = 180°- 100°

⇒x = 80°

In ΔBCF, ∠BCF + ∠BFC + ∠CBF= 180°(Angle sum property)

⇒ x +  ∠BFC +y = 180°

⇒80° + ∠BFC + 60° = 180°

⇒∠BFC = 180° - 140°

⇒∠BFC = 40°

Now, ∠BFC + ∠BFA = 180°

⇒ 40° + z  = 180°

⇒  z  = 180°- 40°

⇒  z  = 140°

∴x = 80°, y = 60°,z  = 140°

Thank U : )

Please mark as the BRAINLIEST if my answer is helpful ( ;

sTaY SaFe

Answer 2

Answer:

z=140⁰

x=80⁰

y=60⁰

Step-by-step explanation:

Explained above.....!!!