Question

please solve this mate ​

Answer 1

Answer:

answer for the given problem is given

Answer 2

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Let no at ones = x

Let no at tens = 10 (x+3)

=10x+30

New no.

Let no at ones place x+3

Let no at tens place 10x

$10x + 30 + x + 10x + x + 3 = 121$

$22x = 88$

$x = \frac{88}{22}$

$x = 4$

The original no is 74

The new no is 47

Hope it helps :)