Question

please solve this mates ​

Answer 1

Answer:-

Your Answers Are:-

• $\bf 2p + q - 5 = 0.$

• The value of k is 12.

Explanation:-

Given Equations:-

• $\tt\dfrac{2x}{3}+\dfrac{y}{6} - 5 = 0.$

• $\tt 2x-3y = k,$ where x = 2 and y = -2.

To,

• Express the first equation in the form of $\tt aX+bY+C = 0.$

• Find the value of k in second equation.

Now,

5)

In first equation let $\bf\dfrac{x}{3}$ be p and $\bf\dfrac{y}{6}$ be q.

By putting above values in equation we get,

$\\ \tt\mapsto\dfrac{2x}{3} + \dfrac{y}{6} - 5 = 0.$

$\\ \large \red{\mapsto \boxed{ \blue{ \bf2p + q - 5 = 0.}}}$

Which is in the required form where,

• p = X = x/3.

• q = Y = y/6.

• (-5) = C.

And,

6)

We have given the value of x and y as 3 and -2 respectively so let us put the value of x and y in the equation:-

$\\ \tt\mapsto2x - 3y = k.$

$\\ \tt\mapsto2(3) - 3( - 2) = k$

$\\ \tt\mapsto 6 - ( - 6) = k.$

$\\\tt\mapsto6 + 6 = k.$

$\\ \tt\mapsto12 = k.$

$\\ \large \red{\mapsto \boxed{ \blue{ \bf k = 12.}}}$

Therefore The Required Value Of k is 12.

Therefore,

Ans. of 5) is $\bf 2p+q-5=0,$ And ans. of 6) ie 12.