Question

please solve this math please help me​

Answer 1

$2 {}^{x} = 3 {}^{ - x} \\ = > 2 {}^{x} = \frac{1}{ {3}^{x} } \\ = > 2 {}^{x} \times {3}^{x} = 1 \\ = > {6}^{x} = 1 \\ = > 6 {}^{0} = 1$

So the value of x is 0

Hope it helps you.. plz mark it as Brainliest answer.. thanks

Answer 2

2^x=3^(-x)

when x=0

2^0=3^0

1=1

so,x=0