please solve this math problem
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this is your answer!!!
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Here it is given that ΔABC and ΔBCD are isoceles.
In triangle ABC,
∠ABC = ∠ACB ( opposite angles are equal in an isoseles triangle ) ⇒ Equation 1.
Now in traingle BCD,
∠DBC = ∠DCB ( opposite angles are equal in an isoceles triangle ) ⇒ Equation 2.
Adding Equation 1 And Equation 2.
We get,
∠ABC + ∠DBC = ∠ACB + ∠DCB.
Now ∠ABC + ∠DBC is ∠ABC and ∠ACB + ∠DCB = ∠ACD.
Hence,
∠ABC = ∠ACD.
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