please solve this Maths question....only if you know..no wrong answers please......
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Answer :D
f(x) = –3x3 – 24x2 – 45x
= – 3x (x2 + 8x + 15) = – 3x (x + 5) (x + 3)
f(x) = 0 ⇒ x = –5, x = –3, x = 0
f ″(x) = –9x2 – 48x – 45 = –3 (3x2 + 16x + 15)
f ″(0) = – 45 < 0
Therefore, x = 0 is point of local maxima f ″(–3) = 18 > 0.
Therefore, x = –3 is point of local minima f ″(–5) = –30 < 0.
Therefore x = –5 is point of local maxima
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Answer :D
f(x) = –3x3 – 24x2 – 45x
= – 3x (x2 + 8x + 15) = – 3x (x + 5) (x + 3)
f(x) = 0 ⇒ x = –5, x = –3, x = 0
f ″(x) = –9x2 – 48x – 45 = –3 (3x2 + 16x + 15)
f ″(0) = – 45 < 0
Therefore, x = 0 is point of local maxima f ″(–3) = 18 > 0.
Therefore, x = –3 is point of local minima f ″(–5) = –30 < 0.
Therefore x = –5 is point of local maxima
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