Question

please solve this
maths word problem class 10th chapter-quadric equation

Answer 1

here's your answer, the 2-digit no.is 23

Answer 2

let the no.s be x and y
according to the question
xy=6.(eq.1)
again 10x+y+9=10y+x.(eq.2)
by the method of substitution
from equation 1
x=6/y
putting the value of x in equation 2 we get
10(6/y)+y+9=10y+(6/y)
60/y+y+9=10y+6/y
60/y-6/y+9=10y-y
54/y+9=9y
54/y-9y=-9