Question

please solve this

my doubt is in answer for d question answer is 3/4 but how

Answer 1

Given that 2 coins are tossed.

(a). The possible outcomes are HH, HT, TH, TT.


(b) Therefore the total number of outcomes is n(S) = 4.


(c) Let A be the event of getting two heads, Then

n(A) = {HH} and therefore, n(A) = 2.

Required probability P(A) = n(A)/n(S)

                                           = 2/4

                                           = 1/2.



(d) Let B be the event of getting at least one head.Then

n(B) = {HT,TH,HH} and therefore n(B) = 3.

Required probability P(B) = n(B)/n(S)

                                           = 3/4.



(e) Let C be the event of getting no heads.Then

n(C) = {TT} and therefore n(C) = 1.

Required probability P(C) = n(C)/n(S)

                                           = 1/4.



(f) Let D be the event of getting only one head.Then

n(D) = {HT,TH} and therefore n(D) = 2.

Required probability p(D) = n(D)/n(S)

                                          = 2/4

                                          = 1/2




Hope this helps!   --------------------- Good Luck.

Answer 2

Answer:

Sorry...........................