Question

please solve this. my friend ask me solve this​

Answer 1

Answer;

ABCD is a parallelogram . In the diagram the area of yellow regions are 8 , 10 , 72 and 79. Find the area of red triangle. The diagram is not to scale.

Solution:

Red triangle area :

79 + 10 - 72 - 8 = 979+10−72−8=9

Do you know why triangle area is 9 ?

It's important to understand the method to verify the answer and the answer and to strengthen problem solving skills.

The key is finding a triangle or set of triangles , who's area = 1/2 the area of the parallelogram.

__________

Important steps :

First label the remaining areas as shown in the figure.

we have labeled red part as x so we know that we have to solve for x.

Solving :

The blue part will be

= \frac{(base) \times (height)}{2}=2(base)×(height)

= \frac{area \: of \: parallelogram}{2}=2areaofparallelogram

= (x + a) + (72 + b + 8)=(x+a)+(72+b+8)

Now , let's solve for orange part

which is ,

= \frac{(base) \times (height)}{2}=2(base)×(height)

= \frac{area \: of \: parallelogram}{2}=2areaofparallelogram

= a + 79 + b + 10=a+79+b+10

If we mix both the part ,

blue and orange part

which will be ,

(x + a) + (72 + b + 8) = a + 79 + b + 10(x+a)+(72+b+8)=a+79+b+10

we will cut a and b from brackets and a and b from outside part

which will be ,

x + 72 + 8 = 79 + 10x+72+8=79+10

So we need to solve for x

So ,

x = 79 + 10 - 72 - 8 = 9x=79+10−72−8=9

Hence , the area of red part = 9

hello yaar

Answer 2

Answer:

$\huge \color {red}answer$

ABCD is a parallelogram . In the diagram the area of yellow regions are 8 , 10 , 72 and 79. Find the area of red triangle. The diagram is not to scale.

$\huge \color{orange}{solution}$

Red triangle area :

79 + 10 - 72 - 8 = 979+10−72−8=9

Do you know why triangle area is 9 ?

It's important to understand the method to verify the answer and the answer and to strengthen problem solving skills.

The key is finding a triangle or set of triangles , who's area = 1/2 the area of the parallelogram.

__________

Important steps :

First label the remaining areas as shown in the figure.

we have labeled red part as x so we know that we have to solve for x.

Solving :

The blue part will be

= \frac{(base) \times (height)}{2}=2(base)×(height)

= \frac{area \: of \: parallelogram}{2}=2areaofparallelogram

= (x + a) + (72 + b + 8)=(x+a)+(72+b+8)

Now , let's solve for orange part

which is ,

= \frac{(base) \times (height)}{2}=2(base)×(height)

= \frac{area \: of \: parallelogram}{2}=2areaofparallelogram

= a + 79 + b + 10=a+79+b+10

If we mix both the part ,

blue and orange part

which will be ,

(x + a) + (72 + b + 8) = a + 79 + b + 10(x+a)+(72+b+8)=a+79+b+10

we will cut a and b from brackets and a and b from outside part

which will be ,

x + 72 + 8 = 79 + 10x+72+8=79+10

So we need to solve for x

So ,

x = 79 + 10 - 72 - 8 = 9x=79+10−72−8=9

Hence , the area of red part = 9