Question

Please solve this. NCERT.​

Answer 1

Answer:

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Step-by-step explanation:

logaˣ-logbˣ                 logaˣ

--------------------- =    -----------------------

logbˣ-logcˣ                  logcˣ

let the base be b

then

logaˣ-1/1-logcˣ=logaˣ/logcˣ

logaˣ-1/1-logcˣ=xloga to the base c

xloga-1/xloga=1-xlogc

1-1/xloga=1-xlogc

1/xloga=xlogc

1=xloga*xlogc

1=(logb to the base b)

logb²ˣ=logacˣ

hence came the given:ac=b²