Question

please solve this NO SPAMS !

Answer 1

Answer:

Option(B)

Step-by-step explanation:

Given:

√3x² - 4x + 34 + √3x² - 4x - 11 = 9    ----- (*)

Let :

(i)

a = √3x² - 4x + 34

On Squaring both sides, we get

a² = 3x² - 4x + 34

(ii)

Let b = √3x² - 4x - 11

On squaring both sides, we get

b² = 3x² - 4x - 11

(iii)

Equation (*) becomes,

a + b = 9

(iv)

We know that a² - b² = (a - b)(a + b)

⇒ 3x² - 4x + 34 - 3x² + 4x + 11 = (a - b)(9)

⇒ 45 = (a - b)(9)

⇒ a - b = 5

On solving (iii) & (iv), we get

a + b = 9

a - b = 5

---------------

2b = 4

b = 2

Substitute b = 2 in (i), we get

⇒ a + b = 9

⇒ a + 2 = 9

⇒ a = 7

So,

√3x² - 4x + 34 = 7

On squaring both sides, we get

⇒ 3x² - 4x + 34 = 49

⇒ 3x² - 9x + 5x + 34 = 49

⇒ 3x² - 9x + 5x - 15 = 0

⇒ 3x(x - 3) + 5(x - 3) = 0

⇒ (3x + 5)(x - 3) = 0

⇒ x = 3, -5/3{Neglect}

⇒ x = 3

Therefore:

√3x² - 4x + 34 + √3x² - 4x - 11 = 3

Hope it helps!

Answer 2

Answer:

☞ X = 3

hope it helps you mate