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Q. Radhika made a Picture of an Aeroplane with Colored paper as shown in the above Attachment. Find the Total area of the paper used.​

Answer 1

Answer:

For the triangle I section:

It is an isosceles triangle and the sides are 5 cm, 1 cm and 5 cm.

Perimeter = 5+5+1 = 11 cm So, semi perimeter = 11/2 cm = 5.5 cm

Using Heron's formula,

Area = v(sis-a)(s-b)(s-c)] = V[5.5(5.5-5)(5.5-5)(5.5-1)] cm²

= V[5.5x0.5x0.5x4.5] cm²

= 0.75/11 cm²

= 0.75 x 3.317cm²

= 2.488cm² (approx)

For the quadrilateral Il section:

This quadrilateral is a rectangle with length and breadth as 6.5 cm and 1 cm respectively. Area = 6.5x1 cm²-6.5 cm²

For the quadrilateral III section:

It is a trapezoid with 2 sides as 1 cm each and the third side as 2 cm. Area of the trapezoid = Area of the parallelogram + Area of the equilateral triangle

The perpendicular height of the parallelogram will be

(√1² – (0.5)²)

= 0.86 cm

And, the area of the equilateral triangle will be (√3/4xa) = 0.43 Area of the trapezoid =0.86+0.43=1.3 cm² (approximately).

For triangle IV and V:

These triangles are 2 congruent right angled triangles having the base as 6 cm and height 1.5

Area triangles IV and V=2x(x6x1.5) cm² = 9 cm²

"So, the total area of the paper used (2.488+6.5+1.3+9) cm² = 19.3 cm²"

hope it helps you!

Answer 2

refer to the attachment

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