Please solve this numerical
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(a) Given= Focal length of convex mirror
F= +15cm
Distance of object (u)= -12 cm
Size of object (O) = 4.5 cm
Using the Mirror Formula,
1/f = 1/v + 1/u
1/15 = 1/v - 1/12
1/v = 1/15 + 1/12 = 4+5/60 = 9/60
(b)Distance of image from the mirror v = 6.7cm
The positive sign shows that the image is formed behind the mirror.
(c) Using the formula of magnification ,
m = -v/u = L/O
-6.7/-12 = L/4.5
Size of image L = 2.5 cm
As L is +ve so image is erect and virtual .
Magnification is given by ,
m = L/O = 2.5/4.5 = 25/45 = 5/9
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