Question

please solve this numerical

Answer 1

Explanation:

option_C

option_a

Mark meh as brainlist please:)

Answer 2

1) Speed=Distance/time

7- 3/9-7

= 4/2

Speed= 2cm/ sec

so correct option is b

2) Distance travelled= Area and closed under velocity time graph

S=A1+A2+A3+A4

From 0 to 1sec

S1= area enclosed & triangle

triangle OAM=1/2×b×h

S1= 1/2 ×1×20=10 m

From 1 sec to 2 sec

S2= b×h = 1×20 m

S2= 20 m

From 0 to 1 sec

S3= base× average height

S3= 1×(20+10/2) = 30/2

S3= 15m

From 3 to 4 sec

S4= Area of rectangle CDOP

S4= base× height= 1×10

S4= 10m

Total distance from 0 to 4 sec

S=S1+S2+S3+S4

S= 10+20+15+10

S= 55m

It's answer is 55....but option main ye nhi h...so i think 50 is answer