Question

Please solve this numerical of ch motion

Answer 1

a =v-u\t
a=20-0\300
=1\15 is a aceleration and
s=ut + 1\2(at)2
s= 0*300+1\2*1\5*(300)2
=90 is your distance

Answer 2

u=0
v=72km/h =20m/s
t=5s
a =v-u/t
a=20-0/5
a=4m/s^2

v^2-u2=2as
400-0=2×4×s
400=8s
s=50m