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In ∆AOP and ∆BOQ
AP=BQ. (Given)
angleAPO=angleOQB (becauseAP//BQ)
angleAOP=angleBOQ(vertically opposite angle
By cong. rule AAS ∆AOP~∆BOQ
AO=BO and PO=QO. (By CPCT)
So,AB and PQ bisect each other.
AP=BQ. (Given)
angleAPO=angleOQB (becauseAP//BQ)
angleAOP=angleBOQ(vertically opposite angle
By cong. rule AAS ∆AOP~∆BOQ
AO=BO and PO=QO. (By CPCT)
So,AB and PQ bisect each other.
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