please solve this one......
In an adjoining figure, DE||BC . If AD=2cm, BD = 5cm , AE= 3cm , then AC is equal to ?
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Step-by-step explanation:
Given: AD=2cm,DB=3cm,AB=5cm
and DE ∣∣BC
Basic Proportionality theorem which states that. if a line is drawn parallel to one side of a triangle the other two sides in distinct points, then the other two sides are divided in the same ratio. So, by basic proportionality theorem.
DB
AD
=
EC
AE
3
2
=
EC
5
EC=
2
5×3
EC=7.5cm
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