Question

please solve this one it's urgent ..​

Answer 1

Answer:

Speed of the police van, Vp = 30 km/h = 8.33 m/s

Muzzle speed of the bullet, Vb = 150 m/s

Speed of the thief's car, Vt = 192 km/h = 53.33 m/s

Since the bullet is fired from a moving van, its resultant speed can be obtained as: = 150 + 8.33 = 158.33 m/s

Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thiefs car can be obtained as:

Vbt = Vb - Vt

= 158.33 - 53.33 = 105 m/s

MARK ME AS BRAINLIEST.

Answer 2

Answer:

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☆Given:-

•The police fan is moving with a speed of 30km h^-1

•The thief car is moving in same direction at a speed of 192km h ^-1

▪The muzzle speed of bullet is 150m/s^-1

☆To prove :-

●We should want to prove the speed ofwhich the relevant for damaging thiefs car.

☆Proof :-

Muzzle speed of bullet is vB= 150 m/s^-1=540km/h^-1

speed of police van is vv=30km/h^-1

Resultant speed of bullet is

v=540+30=570kmh^-1.

●Speed of thief car =vT= 192km h^-1

●The speed with which the bullet hits the thiefs car

v-vT= 570-192= 372km h^-1

☆Verification :-

we should convert 372 km h^-1 into ms^-1

Therefore,

105ms^-1 is the speed of which is relevant for damaging the thiefs car .

Hope it helps u mate .

Thank you.