Math, asked by TANU81, 1 year ago

Please solve this please.......

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Answered by Thatsomeone
4
question number 18
angle DAC + angle DAB=180 .. (angles in linear pair)
let angle DAC be x
angle DAB be y
x+y=180
angle FAD=angle FAC .. ( given)
angle FAD + angle FAC = angle DAC
angle DAE=angle EAB
angle DAE + angle EAB=angle DAB
angle DAC+angle DAB=180
angle DAC/2=angle FAD
angle DAE/2=angle EAD
angle EAD+angle FAD=angle EAF
angle DAE/2+angle DAC/2=angle EAF
(angle DAE+angle DAC) /2=angle EAF
180/2=angle EAF
angle EAF=90
question number 18
angle COB=angle AOD .. (opposite angle)
angle AOD=63
X=63
COB+BOD=180.. (angle in linear pair)
BOD=180-63=117
Y=117
Y=Z.. (opposite angle)
Z=117
hope it helps you







TANU81: Thanks a lot....Okk I check
Thatsomeone: always welcome
TANU81: Ur answer is correct..... ⛎⛎ ♌♌
Thatsomeone: ok.
Thatsomeone: thank you for selecting my answer as brainliest
TANU81: (*^_^*)
Thatsomeone: :)
TANU81: Here,,Read ur answer u write two times question number 18.....I can't understand
TANU81: okkkkhhh alright ,,,Now I understand
Thatsomeone: sorry 1st one is no.17
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