Question

please solve this please​

Answer 1

your answer dued.........

Answer 2

Step-by-step explanation:

f ′ (x) = –3x3 – 24x2 – 45x

= – 3x (x2 + 8x + 15) = – 3x (x + 5) (x + 3)

f ′ (x) = 0 ⇒ x = –5, x = –3, x = 0

f ″(x) = –9x2 – 48x – 45

= –3 (3x2 + 16x + 15)

f ″(0) = – 45 < 0. Therefore, x = 0 is point of local maxima

f ″(–3) = 18 > 0. Therefore, x = –3 is point of local minima

f ″(–5) = –30 < 0. Therefore x = –5 is point of local maxima.