Question

please solve this
please​

Answer 1

Answer:

sorry i don't know but I'm try

Answer 2

$\huge{ \underbrace{ \text{✿Solution}}}$

$\\ \\ \sf{ \frac{x {}^{2} + 2x }{3} \div \frac{x - 3}{x {}^{2} - 9} \times \frac{1}{x {}^{2} - 2x - 8 } } \\ \\ \sf{ = \frac{x(x + 2)}{3} \div \frac{x - 3}{(x) {}^{2} - {3}^{2} } \times \frac{1}{ {x}^{2} - 4x + 2x - 8 } } \\ \\ \sf{ = \frac{x(x + 2)}{3} \div \frac{x - 3}{(x + 3)(x - 3)} \times \frac{1}{x(x - 4) + 2(x - 4)} } \\ \\ \sf{ = \frac{x(x + 2)}{3} \times \frac{(x + 3)(x - 3)}{(x - 3)} \times \frac{1}{(x - 4)(x + 2)} } \\ \\ \sf{ \orange{ = \frac{x(x + 3)}{3( x - 4)} } }$