Math, asked by Anonymous, 3 months ago

please solve this please​

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Answered by Anonymous
13

Hope it helps_________

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Answered by TheBrainController
6

Given :- The sum of the digit of a 2 digit number is 6. On the reversing digits the number is 18 less than the original number.

To find :- The number

Solution :-

Let say original number = AB

A + B = 6

Reversed number = BA

On the reversing it's digits, the number is 18 less than the original number

10B + A = 10A + B - 18

→ 9 ( A - B ) = 18

→ A - B = 2

2A = 8

→ A = 4

→ B = 2

Number = 42

Verification,

4 + 2 = 6

24 = 42 - 18

42 is the number whose sum of the digits is 6 and on reversing it's digits, the number is 18 less than the original number.

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