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Given :- The sum of the digit of a 2 digit number is 6. On the reversing digits the number is 18 less than the original number.
To find :- The number
Solution :-
Let say original number = AB
A + B = 6
Reversed number = BA
On the reversing it's digits, the number is 18 less than the original number
10B + A = 10A + B - 18
→ 9 ( A - B ) = 18
→ A - B = 2
2A = 8
→ A = 4
→ B = 2
Number = 42
Verification,
4 + 2 = 6
24 = 42 - 18
42 is the number whose sum of the digits is 6 and on reversing it's digits, the number is 18 less than the original number.
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