Question

please solve this please ​

Answer 1

Answer:

SOLUTION:- TOTAL NUMBER OF STUDENTS =70

LET A BE THE SET OF STUDENTS WHO LIKES TO PLAY CRICKET

LET B BE THE SET OF STUDENTS WHO LIKES TO PLAY KHO KHO

HENCE THE NUMBER OF STUDENTS WHO LIKES TO PLAY CRICKET OR KHO KHO IS n ( A U B)

= n( A U B) = 70

number of students who likes to play both cricket and KHO KHO is n ( A U B)

n (A) =45, n (B) =52

We know, n (A U B) = n (A) + n ( B) - n (A n B)

= n ( A n B) = n (A) + n (B) - n ( A U B)

= 45+52-70=27

= NUMBER OF STUDENTS WHO LIKES TO PLAY BOTH THE GAMES ARE 27,

NUMBER OF STUDENTS WHO LIKES TO PLAY KHO KHO ARE 45.

= NUMBER OF STUDENTS WHO LIKES TO PLAY CRICKET = 45-27=18

= A n B IS THE SET OF STUDENTS WHO PLAY BOTH THE GAMES THEREFORE n ( A n B) = 27

THANK YOU

HOPE IT HELPS

Answer 2

Answer:

27 students

Step-by-step explanation:

n(A)=45,n(B)=52

So set A=A={students who like to play cricket}

Set B=B={students who like to play kho-kho}

Hence n(A)=45,n(B)=52n(A)=45,n(B)=52

We know that n(A∪B)n(A∪B) is the set of students

who like to play at least one of the two games.

So n(A∪B)=70n(A∪B)=70 and n(A∩B)n(A∩B) are those who like to play both the games and we know the formula that

n(A∪B)=n(A)+n(B)−=n(A)+n(B)−n(A∩B)

Hence we know the formula that

n(A∪B)n(A∪B)=n(A)+n(B)−=n(A)+n(B)−n(A∩B)n(A∩B)

n(A)n(A) represents number of students liking cricket

n(B)n(B) represents number of students who like kho-kho

n(A∪B)n(A∪B) are the number of students liking at least one game

n(A∩B)n(A∩B) are those who like both the games.

7070=45+52−=45+52−n(A∩B)n(A∩B)

Hence we get that

n(A∩B)=97−70=27n

So those who like both the games are 27 students

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