Question

Please solve this. Please don’t give silly answers.

Answer 1

Answer:

HOPE THESE BRING A SMILE IN YOUR FACE

Step-by-step explanation:

Answer 2

Answer:

i)$x^2-\left(\frac{3}{2}+\frac{3}{2}\right)x+\frac{9}{4}$    (same zeroes)

=$x^2-\left(3\right)x+\frac{9}{4}$

ii)$x^2-\left(\sqrt{6}-\sqrt{6}\right)x+\sqrt{6}\left(-\sqrt{6}\right)$    

=x^2-6

iii)$x^2-\left(\frac{4}{5}+\frac{5}{4}\right)x+\frac{4}{5}\cdot \frac{5}{4}$               (inverse of another zero)

=$x^2-\frac{41x}{20}+1$

iv)$x^2-\left(3-\sqrt{2}+3+\sqrt{2}\right)x+3-\sqrt{2}\cdot \:3+\sqrt{2}$  

=$x^2-6x+3-2\sqrt{2}$

Step-by-step explanation: