please solve this please please
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here is your answer by Sujeet,
Given that cos A=4/5=b/h
by Pythagoras theorem
h²=p²+b²
5²=p²+4²
p²=5²-4²
p²=25-16
p²=9
p=√9
p=3
then,
cot A=b/p=4/3
sinA =p/h=3/5
tan A=p/b=3/4
then,
value of,
cot -sin/2tan
4/3-3/5 /2*3/4
11/15 / 3/2
11/15*2/3
22/45
that's all..........................
Sujeet.....
Given that cos A=4/5=b/h
by Pythagoras theorem
h²=p²+b²
5²=p²+4²
p²=5²-4²
p²=25-16
p²=9
p=√9
p=3
then,
cot A=b/p=4/3
sinA =p/h=3/5
tan A=p/b=3/4
then,
value of,
cot -sin/2tan
4/3-3/5 /2*3/4
11/15 / 3/2
11/15*2/3
22/45
that's all..........................
Sujeet.....
vaishali12:
thank u very much
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