Please solve this probability question with clear steps.
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As A and B are visiting the shop from Tuesday to Saturday, for 5 probable days. Therefore total number of probable days are 5x5 = 25.
Now possible events are,
TT, TW, TTHURS, TF, TS
WT, WW, WTHURS, WF, WS
THURST, THURSW, THURSF,THURSSATURDAY,THURSDAY THURSDAY,
FT, FW, FTHURS, FF, FSAT,
ST, SW, STHURS, SF, SATSAT.
1) Probability of reaching the same day = 5/25 = 1/5
2) Probability of reaching the store on consecutive days = 8/25
3) Probability of reaching the store on different days = 1-1/5 =4/5
Now possible events are,
TT, TW, TTHURS, TF, TS
WT, WW, WTHURS, WF, WS
THURST, THURSW, THURSF,THURSSATURDAY,THURSDAY THURSDAY,
FT, FW, FTHURS, FF, FSAT,
ST, SW, STHURS, SF, SATSAT.
1) Probability of reaching the same day = 5/25 = 1/5
2) Probability of reaching the store on consecutive days = 8/25
3) Probability of reaching the store on different days = 1-1/5 =4/5
himanilak:
Thank you much....best explanation :)
I hope you did not have difficulty in understanding the events as the week days were represented as the initials of those days.
Happy to hear that it helped u
no troubles....as i said...BEST EXPLANATION
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