Math, asked by ayusman57, 8 months ago

please solve this problem​

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Answered by RudranilChatterjee
0

Answer:

n = (( \sqrt{ 3 + 2 \sqrt{2} }  +  \sqrt{3 - 2 \sqrt{2} }  ) \div  \sqrt{ \sqrt{3 }  + 1} ) - 2 \sqrt{ \sqrt{3}  - 1} on both sides squaring

 {n}^{2}  = ((3 + 2 \sqrt{2}  + 3 - 2 \sqrt{2} ) \div  \sqrt{3}  + 1) - 2 \sqrt{3}  - 1

 {n}^{2}  = ((5 \sqrt{2}  +  1 \sqrt{2} ) \div  \sqrt{3}  + 1) - 2 \sqrt{3}  - 1

On calculating......

 {n}^{2}  = 1.4348778704 \\  n  \:  \:  = 1.1978638781

I think so

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