Math, asked by mazerunner5, 6 months ago

please solve this problem.​

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Answered by Anonymous
23

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Correct Question

√2x² + 7x + 5√2=0 to solve this quadratic equation by factorisation?

Answer

Zeros are -5/√2 , √2

Given

√2x² + 7x + 5√2=0

To Calculate

zeros _?

Explanation

√2x² + 7x + 5√2=0

\longrightarrow √2x²+(5+2)x+5√2=0

\longrightarrow√2x²+5x+2x+5√2=0

\longrightarrow√2x²+5x+√2×√2x+5√2=0

\longrightarrow(√2x+5)+√2(√2x+5)=0

\longrightarrow( √2x+5)(x+√2) =0

\longrightarrow√2x+5=0, x+√2=0

\longrightarrow x= -5/√2 , x= -√2

Hence,

Zeros are -5/√2 , √2

━━═━═━═━═━═━━═━═━═━═━═━━═━

⭐ Additional information ⭐

1) Sum of zeros = -b/a

2) Product of zeros = c/a

━━═━═━═━═━═━━━═━═━═━═━═━

Answered by Anonymous
3

Answer:

Correct Question

√2x² + 7x + 5√2=0 to solve this quadratic equation by factorisation?

Answer

Zeros are -5/√2 , √2

Given

√2x² + 7x + 5√2=0

To Calculate

zeros _?

Explanation

√2x² + 7x + 5√2=0

\longrightarrow⟶ √2x²+(5+2)x+5√2=0

\longrightarrow⟶ √2x²+5x+2x+5√2=0

\longrightarrow⟶ √2x²+5x+√2×√2x+5√2=0

\longrightarrow⟶ (√2x+5)+√2(√2x+5)=0

\longrightarrow⟶ ( √2x+5)(x+√2) =0

\longrightarrow⟶ √2x+5=0, x+√2=0

\longrightarrow⟶ x= -5/√2 , x= -√2

Hence,

Zeros are -5/√2 , √2

━━═━═━═━═━═━━═━═━═━═━═━━═━

⭐ Additional information ⭐

1) Sum of zeros = -b/a

2) Product of zeros = c/a

━━═━═━═━═━═━━━═━═━═

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