Math, asked by Anonymous, 6 months ago

please solve this problem. 30​

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Answered by sdennis1806
2

Answer:

(i)

AC∧2=AB∧2+BC∧2  (Pythagoras theorem)

AC∧2=(50)∧2+(120)∧2

        =2500+14400

        =16900

AC=√16900

     =130 m

(ii)

perimeter= 2(l+b)

               =2(120+50)

               =2(170)

               =340 cm

(iii) area of one triangle=bh/2

                                     =120x50/2

                                     =6000/2

                                    = 3000m∧2      

(iv) total area  of the rectangle: b xh

                                                  =120 x 50

                                                  =6000 m∧2

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Answered by Anonymous
1

Answer: ur required answer Ayan ;-

1st QUESTION :

∴ SOLUTION ⇒

AC²  = AB ² + BC² ............ ( By pythagoras theorem )

AC² =  ( 50 )² + ( 120 ) ²

AC ² = 2500 + 14400

AC ² = 16900

AC = √ 16900

AC = 130 m

2nd QUESTION :

∴ SOLUTION ⇒

Perimeter = 2 ( l + b ) ........ ( where l = length and b = breadth )

⇒ 2 ( 120 + 50 )

⇒ 2 × 170

⇒ 340 m

3rd QUESTION :

∴ SOLUTION ⇒

Area of triangle = b × h / 2 ........... ( where b =  base and h = height )

⇒ 120 × 50 / 2

⇒ 6000 /2

⇒ 3000 m ²

4th QUESTION :

∴ SOLUTION ⇒

Area of rectangle =  l × b

⇒ 120 × 50

⇒ 6000 m ²

Step-by-step explanation:

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