please solve this problem. 30
Answers
Answer:
(i)
AC∧2=AB∧2+BC∧2 (Pythagoras theorem)
AC∧2=(50)∧2+(120)∧2
=2500+14400
=16900
AC=√16900
=130 m
(ii)
perimeter= 2(l+b)
=2(120+50)
=2(170)
=340 cm
(iii) area of one triangle=bh/2
=120x50/2
=6000/2
= 3000m∧2
(iv) total area of the rectangle: b xh
=120 x 50
=6000 m∧2
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Answer: ur required answer Ayan ;-
1st QUESTION :
∴ SOLUTION ⇒
AC² = AB ² + BC² ............ ( By pythagoras theorem )
AC² = ( 50 )² + ( 120 ) ²
AC ² = 2500 + 14400
AC ² = 16900
AC = √ 16900
AC = 130 m
2nd QUESTION :
∴ SOLUTION ⇒
Perimeter = 2 ( l + b ) ........ ( where l = length and b = breadth )
⇒ 2 ( 120 + 50 )
⇒ 2 × 170
⇒ 340 m
3rd QUESTION :
∴ SOLUTION ⇒
Area of triangle = b × h / 2 ........... ( where b = base and h = height )
⇒ 120 × 50 / 2
⇒ 6000 /2
⇒ 3000 m ²
4th QUESTION :
∴ SOLUTION ⇒
Area of rectangle = l × b
⇒ 120 × 50
⇒ 6000 m ²
Step-by-step explanation:
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