Question

please solve this problem

Answer 1

if n=1, then n+2=3,n+4=5 (only 3 is divisible)
if n=2,then n+2=4,n+4=6 (only 6 is divisible )
if n=3,then n+2=5,n+4=7 (only 3 is divisible )

so we can say that there are one nd only one out of n, n+2, n+4 is divisible by 3

Answer 2

♧♧HERE IS YOUR ANSWER♧♧

Given terms are :

n, n + 2 and n + 4.

When n = 1,

n = 1

n + 2 = 1 + 2 = 3, divisible by 3

n + 4 = 1 + 4 = 5

When n = 2,

n = 2

n + 2 = 2 + 2 = 4

n + 4 = 2 + 4 = 6, divisible by 3

When n = 3,

n = 3, divisible by 3

n + 2 = 3 + 2 = 5

n + 4 = 3 + 4 = 7

. . .
. . .
. . .

So, one and only one out of n, n+ 2 and n + 4 is divisible by 3. [Proved]

♧♧HOPE THIS HELPS YOU♧♧