Question

please solve this problem

Answer 1

let R1 ,R2,R3,R4,R5 and R6 are equal to 2 ohm
and R1 ,R2 and R3,R4 and R5 , and R6 are connected in parallel then by formula

1/R1 +1/R2+R3 +1/R4+R5 +1/R6=1/R
1/2 +1/2+2 +1/2+2 +1/2=1/R
$2 + 1 + 1 + 2 \div 4$
6/4=1/R
R=1.5 ohm answar
the total resistance between AB is 1.5 ohm

Answer 2

good answer always has a bad remark