Math, asked by singhranjeetkumar065, 3 days ago

please solve this problem​

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Answers

Answered by Amitrai1234
5

Answer:

tan (90-A)×cotA

sec(90-A)×cosecA

Step-by-step explanation:

cotA×cotA

cosecA ×cosecA

cos2A/sin2A×sin2A=

cos2A

Answered by rrai92244
0

Answer:

  1. tan(90-A)×cot A
  2. sec(90-A)×cosec A
  3. cotA×cot A
  4. cosec A ×cosec A
  5. cos2A/sin2A×sin2A
  6. = cosec2A

Step-by-step explanation:

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