please solve this problem?
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(438)₁₀
16 ÷438 = 27
remainder = 6
16÷27 = 1
remainder = 11
Hence, hexadecimal no. is = (611) => (6B)₁₆
16 ÷438 = 27
remainder = 6
16÷27 = 1
remainder = 11
Hence, hexadecimal no. is = (611) => (6B)₁₆
utsav46:
from where you are
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0
Result of converting:
43810 = 1B616
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