Question

please solve this problem​

Answer 1

Answer:

Z 0 0 M

5252 25 0717

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Pas-11111

Answer 2

Answer:

3-2√2/3+2√2

Now rationalizing the denominator

3-2√2/3+2√2×3-2√2

3-2√2/3+2√2×3-2√2= (3)2 + (2√2)2 / (3)2 - (2√2)2

3-2√2/3+2√2×3-2√2= (3)2 + (2√2)2 / (3)2 - (2√2)2= 9 + 4×2 / 9 - 4×2

3-2√2/3+2√2×3-2√2= (3)2 + (2√2)2 / (3)2 - (2√2)2= 9 + 4×2 / 9 - 4×2= 9 + 8 / 9 - 8

3-2√2/3+2√2×3-2√2= (3)2 + (2√2)2 / (3)2 - (2√2)2= 9 + 4×2 / 9 - 4×2= 9 + 8 / 9 - 8= 1

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