Physics, asked by rk6070067, 5 hours ago

please solve this problem​

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Answers

Answered by adityaprsona12
0

Answer:

Explanation :

\underline{\underline{\sf{\purple{Given\::-}}}}

Given:−

Two numbers are in ratio 4 : 5

Difference of their cubes = 61

\underline{\underline{\sf{\purple{To\:Find\::-}}}}

ToFind:−

Numbers = ?

\underline{\underline{\sf{\purple{Solution\::-}}}}

Solution:−

Here, we have ratio, i.e, 4 : 5 of two numbers and the difference of their cubes, i.e, 61 we have to find out both numbers. We will set up an equation by understanding the given conditions.

Let the numbers be 4n and 5n

Atq,

\qquad\longrightarrow\quad\sf (5n)^3 - (4n)^3 = 61⟶(5n)

3

−(4n)

3

=61

\qquad\longrightarrow\quad\sf 125n^3 - 64n^3 = 61⟶125n

3

−64n

3

=61

\qquad\longrightarrow\quad\sf 61n^3 = 61⟶61n

3

=61

\qquad\longrightarrow\quad\sf n^3 = \dfrac{61}{61}⟶n

3

=

61

61

\qquad\longrightarrow\quad\sf n^3 = \dfrac{\cancel{61}}{\cancel{61}}⟶n

3

=

61

61

\qquad\longrightarrow\quad\sf n^3 = 1⟶n

3

=1

\qquad\longrightarrow\quad\sf n = \sqrt[3]{1}⟶n=

3

1

\qquad\longrightarrow\quad\bf {n = \pink{1}}⟶n=1

Hence,

First number = 4n = 4 × 1 = 4

Second number = 5n = 5 × 1 = 5

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