Question

please solve this problem​

Answer 1

Answer:

$\sqrt{ {x}^{2} + {y}^{2} - 6x - 6y + 18}$

Step-by-step explanation:

$\sqrt{ {(3 - x)}^{2} + {( - 3 + y)}^{2} } \\ = \sqrt{9 - 6x + {x}^{2} + 9 - 6y + {y}^{2} } \\= \sqrt{ {x}^{2} + {y}^{2} - 6x - 6y + 18}$