please solve this problem
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Step-by-step explanation:
from the triangle BAD
25^2=15^2+BD^2
BD^2=625-225=400
BD=20
so cosx= 20/25= 4/5
from the triangle ADC
AC^2= DC^2+AD^2
17^2=15^2+DC^2
DC^2= 17^2-15^2 = (17-15)(17+15)=2*32= 64
DC=8
so siny= DC/AC = 8/17
so cosx+siny = 4/5+8/17
= (68+40)/85
= 108/85
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