Question

Please solve this problem

Answer 1

Answer:

$( {8a}^{3} - 27 {x}^{ - 3} ) ^{ \frac{ - 1}{3} } \\(2a)^{3} - ( \frac{1}{27 {x}^{3} } )^{ \frac{ - 1}{3} } \\ ((2a) ^{3} - (\frac{1}{(3x )^{3} }) )^{ \frac{ - 1}{3} } \\ \frac{1}{2a} - (\frac{1}{ \frac{1}{3x}} ) \\ ( \frac{1}{2a} - \frac{1}{3x} ) \\ = \frac{3x - 2a}{6ax}$

hope this might help you