Question

please solve this problem ​

Answer 1

$log_{2}(3) = x \\ log_{2}(5) = y \\ prime \: factorization \: of \: 60 \: in \: terms \: of \: 3 \: and \: 5 \\ 60 = {2}^{2} \times 3 \times 5 \\ log_{2}(60) = log_{2}( {2}^{2} \times 3 \times 5 ) \\ log_{2}( {2}^{2} ) + log_{2}(3) + log_{2}(5) \\ 2 log_{2}(2) + x + y \\ 2(1) + x + y \\ log_{2}(60) = x + y + 2$

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