please solve this problem
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HEY MATE,HERE'S UR ANS ↓↓
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GIVEN, OR perpendicular to PQ
R.T.P :- ∠ ROS = 1/2 (∠QOS - ∠POS)
PROOF :- ∵ OR PERPENDICULAR TO PQ
∴ ∠ ROQ = ∠ ROP = 90°
NOW, ∠QOS = ∠ ROQ + ∠ROS
⇒ ∠ QOS = ∠ROP + ∠ROS
⇒ ∠QOS = ∠ROP + ∠ ROS
⇒ ∠QOS = ∠POS + ∠ROS + ∠ROS
⇒ ∠QOS - ∠POS = 2∠ ROS
⇒ 1/2 (∠ QOS - ∠ POS ) =∠ROS
_____________________
HOPE IT HELPS ☺☺✌
___________________________
GIVEN, OR perpendicular to PQ
R.T.P :- ∠ ROS = 1/2 (∠QOS - ∠POS)
PROOF :- ∵ OR PERPENDICULAR TO PQ
∴ ∠ ROQ = ∠ ROP = 90°
NOW, ∠QOS = ∠ ROQ + ∠ROS
⇒ ∠ QOS = ∠ROP + ∠ROS
⇒ ∠QOS = ∠ROP + ∠ ROS
⇒ ∠QOS = ∠POS + ∠ROS + ∠ROS
⇒ ∠QOS - ∠POS = 2∠ ROS
⇒ 1/2 (∠ QOS - ∠ POS ) =∠ROS
_____________________
HOPE IT HELPS ☺☺✌
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