Question

please solve this problem

Answer 1

The only force acting on the block is

mg×sin(alpha)

As the downward acting mg×cos(alpha) is neutralized by normal reaction

F=ma

mgsin(alpha)=ma

a= gsin(alpha)

a= 9.81sin(alpha) m/s^2

When you bring tension 'T' into action you get

mgsin(alpha) - T = m × gsin(alpha)

T = 0

Therefore, your effective acceleration of the wedge with mass 'm' will be

9.81sin(alpha) m/s^2