please solve this problem
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3×4-4y=12
12-4y=12
-4y=12-12
y=0÷-4
y=0
12-4y=12
-4y=12-12
y=0÷-4
y=0
ritik200433:
welcome
Answered by
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☺️hey mate! here's your answer!☺️
(11)
(i) when x = 4
substituting its value in the equation,
3×4 - 4y = 12
=> 12 - 4y = 12
=> 4y = 12 -12
=> y = 0 ...Answer
(ii) when x = 0
substituting its value in the equation,
3×0 + 4y = 12
=> 0 + 4y = 12
=> 4y = 12-0
=> y = 12/4
=> y = 3 ....Answer
hope it is helpful ✌️!
(11)
(i) when x = 4
substituting its value in the equation,
3×4 - 4y = 12
=> 12 - 4y = 12
=> 4y = 12 -12
=> y = 0 ...Answer
(ii) when x = 0
substituting its value in the equation,
3×0 + 4y = 12
=> 0 + 4y = 12
=> 4y = 12-0
=> y = 12/4
=> y = 3 ....Answer
hope it is helpful ✌️!
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