please solve this problem...
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####HELLO FRIEND####
####HERE IS YOUR ANSWER####
=> It is given that ,
cos B = sin A / 2 sin C
2sinBcosC=sinA
sin(B+C)+sin(B-C)=sinA
sin(180-A)+sin(B-C)=sinA
sinA+sin(B-C)=sinA
sin(B-C)=0
B-C=0
B=C
=> AB = AC
HENCE ABC IS ISOSCELES TRIANGLE
####HERE IS YOUR ANSWER####
=> It is given that ,
cos B = sin A / 2 sin C
2sinBcosC=sinA
sin(B+C)+sin(B-C)=sinA
sin(180-A)+sin(B-C)=sinA
sinA+sin(B-C)=sinA
sin(B-C)=0
B-C=0
B=C
=> AB = AC
HENCE ABC IS ISOSCELES TRIANGLE
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3
Step-by-step explanation:
Answer in the figure.
Hope this will help you.
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