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vicky6644:
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suppose
A(2,1)=(x1,y1)
B=(5,-8)=(x2,y2)
p=(x,y)
m:n=1:2
by section formula,
x=mx1+nx2/m+n
= 1(2)+2(2)/1+2
= 2+4/3
=6/3
=2
y=my+ny2/m+n
=1(1)+2(-8)/1+2
=1-16/3
=-15/3
=-5
therefore co ordinates of point p are (2,-5)
A(2,1)=(x1,y1)
B=(5,-8)=(x2,y2)
p=(x,y)
m:n=1:2
by section formula,
x=mx1+nx2/m+n
= 1(2)+2(2)/1+2
= 2+4/3
=6/3
=2
y=my+ny2/m+n
=1(1)+2(-8)/1+2
=1-16/3
=-15/3
=-5
therefore co ordinates of point p are (2,-5)
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